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e^iπ + 1 = 0 ∫_−∞^∞ e^−x²dx = √π (iγ^μ∂_μ − m)ψ = 0 ∑_n=1^{∞ 1}⁄_n² = ^π²⁄₆ sin(2z) = 2sin(z)cos(z) [

1	2	0
1	2	0
0	1	1

] ∇ × B = μ₀ J ∫ sin 2z dz Δψ = λψ E = mc² d/dx (eˣ) = eˣ ℝⁿ → ℂ